Question

помогите решить задачи,с подробным объеснением как надо.1.сколько граммов соли образуется, если с 20 граммами оксида фосфора (5) прореагировал оксид калия? 2.Сколько оксида азота(2) образуется, если с 20 г N2 прореагировал кислород?​

Answer 1

Ответ:помогитееееееееееееееееееее

Объяснение:

Answer 2

Task 1: How many grams of salt are formed if 20 grams of phosphorus oxide (P2O5) reacts with potassium oxide (K2O)?

To solve this problem, we need to determine the balanced chemical equation for the reaction between phosphorus oxide (P2O5) and potassium oxide (K2O). Once we have the balanced equation, we can use stoichiometry to calculate the amount of salt formed.

The balanced chemical equation for the reaction between P2O5 and K2O is:

P2O5 + 2K2O → 2KPO3

From the balanced equation, we can see that 1 mole of P2O5 reacts with 2 moles of K2O to produce 2 moles of KPO3.

To calculate the amount of salt formed, we need to convert the given mass of P2O5 to moles using its molar mass, and then use the stoichiometric ratio to find the moles of KPO3 formed. Finally, we can convert the moles of KPO3 to grams using its molar mass.

Here are the steps to solve the problem:

1. Calculate the molar mass of P2O5: - P: 2 atoms x atomic mass of P = 2 x 31.0 g/mol = 62.0 g/mol - O: 5 atoms x atomic mass of O = 5 x 16.0 g/mol = 80.0 g/mol - Molar mass of P2O5 = 62.0 g/mol + 80.0 g/mol = 142.0 g/mol

2. Convert the given mass of P2O5 to moles: - Moles of P2O5 = Mass of P2O5 / Molar mass of P2O5 - Moles of P2O5 = 20 g / 142.0 g/mol ≈ 0.141 moles

3. Use the stoichiometric ratio to find the moles of KPO3 formed: - Moles of KPO3 = Moles of P2O5 x (2 moles of KPO3 / 1 mole of P2O5) - Moles of KPO3 = 0.141 moles x (2 moles of KPO3 / 1 mole of P2O5) = 0.282 moles

4. Calculate the mass of KPO3 formed: - Mass of KPO3 = Moles of KPO3 x Molar mass of KPO3 - Molar mass of KPO3 = 2 x atomic mass of K + atomic mass of P + 3 x atomic mass of O - Molar mass of KPO3 = 2 x 39.1 g/mol + 31.0 g/mol + 3 x 16.0 g/mol = 174.1 g/mol - Mass of KPO3 = 0.282 moles x 174.1 g/mol ≈ 49.2 grams

Therefore, approximately 49.2 grams of salt (KPO3) are formed when 20 grams of phosphorus oxide (P2O5) reacts with potassium oxide (K2O).