Question

Срочно!!! Даю 100 б! При взаимодействии этанола массой 4.6 г с калием выделился газ. Какой объем газа выделился?​

Answer 1

Ответ:

Легендарный ответ

Объяснение:

Дано: m(C2H5OH)=4,6г; V(H2)=1л

Найти: W(H2)=?

Решение:

1) n=m/M

n(C2H5OH)=4,6г/46=0,1 моль

2) По закону Авогадро Vm=22,4 л/моль

V=n*Vm

V(C2H5OH)=0,1*22,4л/моль= 2,24 л

Answer 2

Calculating the Volume of Gas Produced

To calculate the volume of gas produced when ethanol with a mass of 4.6 g reacts with potassium, we can use the ideal gas law equation:

PV = nRT

Where: - P = pressure of the gas - V = volume of the gas - n = number of moles of the gas - R = ideal gas constant - T = temperature in Kelvin

First, we need to find the number of moles of the gas produced. To do this, we can use the molar mass of ethanol and the balanced chemical equation for the reaction.

The balanced chemical equation for the reaction between ethanol and potassium is:

C2H5OH + K → ?

Let's find the molar mass of ethanol and calculate the number of moles of ethanol.

The molar mass of ethanol (C2H5OH) can be calculated as follows: - Carbon (C) has a molar mass of 12.01 g/mol - Hydrogen (H) has a molar mass of 1.008 g/mol - Oxygen (O) has a molar mass of 16.00 g/mol

So, the molar mass of ethanol (C2H5OH) is: 12.01 * 2 + 1.008 * 6 + 16.00 + 1.008 = 46.07 g/mol

Now, we can calculate the number of moles of ethanol: Number of moles = Mass / Molar mass Number of moles = 4.6 g / 46.07 g/mol Number of moles = 0.1 mol

Now, we need to determine the stoichiometry of the reaction to find the number of moles of gas produced. Unfortunately, the specific reaction and its stoichiometry are not provided in the question or the search results. Therefore, without the specific reaction, it's not possible to calculate the exact volume of gas produced.

If you have the specific balanced chemical equation for the reaction between ethanol and potassium, please provide it, and I can help you calculate the volume of gas produced.