Question

Какой объем будут занимать 40г f2 и 124г оксида углерода iv. СРОЧНО!

Answer 1

Ответ:

всё зависит от условий, но если нормальные, то:

n(CO2)=4.4/12+32=0.1моль

V(CO2)=0.1*22.4г/мл=2.24мл(н.у.)

Answer 2

Volume Calculation for 40g of F2 and 124g of Carbon Dioxide (CO2)

To calculate the volume occupied by 40g of F2 and 124g of carbon dioxide (CO2), we can use the ideal gas law and molar volume at standard temperature and pressure (STP).

1. Calculate the moles of each substance: - For F2: - The molar mass of F2 (fluorine gas) is approximately 38.00 g/mol. - Therefore, the number of moles of F2 can be calculated as: ``` moles of F2 = mass of F2 / molar mass of F2 = 40g / 38.00 g/mol ≈ 1.05 moles ```

- For CO2: - The molar mass of CO2 (carbon dioxide) is approximately 44.01 g/mol. - Therefore, the number of moles of CO2 can be calculated as: ``` moles of CO2 = mass of CO2 / molar mass of CO2 = 124g / 44.01 g/mol ≈ 2.82 moles ```

2. Use the molar volume at STP to calculate the volume: - At standard temperature and pressure (STP), the molar volume of an ideal gas is approximately 22.4 liters/mol.

3. Calculate the volume occupied by each substance: - For F2: ``` volume of F2 = moles of F2 * molar volume at STP ≈ 1.05 moles * 22.4 L/mol ≈ 23.52 liters ```

- For CO2: ``` volume of CO2 = moles of CO2 * molar volume at STP ≈ 2.82 moles * 22.4 L/mol ≈ 63.29 liters ```

Therefore, the volume occupied by 40g of F2 and 124g of CO2 at STP would be approximately 23.52 liters and 63.29 liters, respectively. [[1]]