Question

Обчисліть масу етанової кислоти, на нейтралізацію якої витратили розчин калій гідроксиду масою 70 г з масовою часткою лугу 8%

Answer 1

Ответ:

СH3COOH + KOH = CH3COOK + H2O

n(CH3COOH)=n(KOH)

m(KOH)=70*0.08=5,6 грамм

n(KOH)=5.6/56=0.1 моль

m(CH3COOH)=0.1*60=6 грамм

Answer 2

Calculating the Mass of Ethanoic Acid Neutralized by Potassium Hydroxide

To calculate the mass of ethanoic acid neutralized by potassium hydroxide, we can use the equation:

Moles = Mass / Molar Mass

First, we need to find the moles of potassium hydroxide used in the neutralization reaction. Then, we can use the balanced chemical equation to determine the moles of ethanoic acid and finally calculate its mass.

Moles of Potassium Hydroxide (KOH)

The molar mass of potassium hydroxide (KOH) is 56.11 g/mol. Given that 70 g of KOH was used, we can calculate the moles of KOH as follows:

Moles of KOH = Mass of KOH / Molar Mass of KOH Moles of KOH = 70 g / 56.11 g/mol

The moles of KOH can be calculated using the above formula.

Balanced Chemical Equation

The neutralization reaction between ethanoic acid (CH3COOH) and potassium hydroxide (KOH) can be represented by the following balanced chemical equation:

CH3COOH + KOH → CH3COOK + H2O

From the balanced chemical equation, we can see that 1 mole of ethanoic acid reacts with 1 mole of potassium hydroxide.

Moles of Ethanoic Acid (CH3COOH)

Since the moles of KOH and CH3COOH are equal due to the balanced chemical equation, the moles of ethanoic acid can be calculated as:

Moles of CH3COOH = Moles of KOH

Calculating the Mass of Ethanoic Acid

Now, we can calculate the mass of ethanoic acid using the moles of CH3COOH and its molar mass.

The molar mass of ethanoic acid (CH3COOH) is approximately 60.05 g/mol.

Mass of CH3COOH = Moles of CH3COOH × Molar Mass of CH3COOH

The mass of ethanoic acid can be calculated using the above formula.

By following these steps, we can determine the mass of ethanoic acid neutralized by the given mass of potassium hydroxide.