Question

Даю 50 баллов.Какую массу метанола сожгли, если в результате реакции выделилось 3 моль СО2?​

Answer 1

Ответ:

2CH3OH+3O2=2CO2+4H2O

1)Сначала найдем моли метанола:

при 2 молях метанола образовывается 2 моль СО2

при Х молях образовывается 3 моль СО2

Х=3

2)Рассчитаем массу метанола

m(масса метанола)=v(моль метанола)×Мr(молярная масса метанола)

v=3

Мr=32

m=?

m=3×32=96

Ответ:96

Answer 2

Calculating the Mass of Methanol Burned

To calculate the mass of methanol burned, we can use the balanced chemical equation for the combustion of methanol, which is:

CH4 + 2O2 → CO2 + 2H2O

From the given information, we know that 3 moles of CO2 were produced as a result of the reaction.

Using the stoichiometry of the balanced chemical equation, we can determine the molar ratio between CH4 and CO2. From the balanced equation, we can see that 1 mole of CH4 produces 1 mole of CO2. Therefore, 3 moles of CO2 would correspond to 3 moles of CH4.

Now, to calculate the mass of methanol burned, we need to know the molar mass of methanol, which is approximately 32 g/mol.

So, the mass of methanol burned can be calculated using the following formula:

Mass = Number of moles × Molar mass

Substituting the values: Mass = 3 moles × 32 g/mol = 96 g

Therefore, the mass of methanol burned is approximately 96 grams.

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