Question

СРОЧНОО.обчисліть масу солі яку одержали внаслідок взаімодії 5 моль NaOH з сульфур(6) оксидом

Answer 1

Ответ:

Дано:

n(NaOH)=5 моль

m(Na2SO4) - ?

5 моль х моль

2NaOH + SO3 => Na2SO4 + H2O

2 моль 1 моль

5:2=х:1

х=5:2

х=2.5 моль (Na2SO4)

n=m:M

m=n•M

m(Na2SO4)=2.5 • 142=355 г

M(Na2SO4)=23•2+32+16•4=142 г/моль

Відповідь: m(NaOH)=355 г

Answer 2

Calculating the Mass of Salt Produced from the Reaction of 5 Moles of NaOH with Sulfur(6) Oxide

To calculate the mass of salt produced from the reaction of 5 moles of NaOH with sulfur(6) oxide, we first need to determine the balanced chemical equation for the reaction between NaOH and sulfur(6) oxide. Once we have the balanced equation, we can use stoichiometry to calculate the mass of salt produced.

The balanced chemical equation for the reaction between NaOH and sulfur(6) oxide is as follows:

2 NaOH + SO3 → Na2SO4 + H2O

Now, let's proceed with the calculation.

Step 1: Determine the Molar Ratio

The balanced chemical equation shows that 2 moles of NaOH react with 1 mole of SO3 to produce 1 mole of Na2SO4. This gives us the molar ratio of NaOH to SO3 as 2:1.

Step 2: Calculate the Moles of SO3

Since we have 5 moles of NaOH, we need to calculate the moles of SO3 required for the reaction. Using the molar ratio from the balanced equation, we can calculate the moles of SO3 as follows:

5 moles NaOH * (1 mole SO3 / 2 moles NaOH) = 2.5 moles SO3

Step 3: Calculate the Molar Mass of Na2SO4

The molar mass of Na2SO4 can be calculated as follows: Na: 22.99 g/mol S: 32.07 g/mol O: 16.00 g/mol Molar mass of Na2SO4 = 2(22.99) + 32.07 + 4(16.00) = 142.04 g/mol

Step 4: Calculate the Mass of Na2SO4 Produced

Now that we know the moles of SO3 and the molar mass of Na2SO4, we can calculate the mass of Na2SO4 produced: Mass = moles * molar mass Mass = 2.5 moles * 142.04 g/mol = 355.1 g

The mass of Na2SO4 produced from the reaction of 5 moles of NaOH with sulfur(6) oxide is 355.1 grams.