Question

Помогите решить химию подалуйста. 120г мрамора, содержащего 10% примесей, обработали соляной кислоты. Определите, какой объём газа выделится, если выход продукта равен 90%.

Answer 1

Всё написал в блокноте, если что непонятно, то пишите - я объясню.

Answer 2

Task: Calculating Gas Volume Produced from Marble Reaction

To solve this problem, we need to calculate the volume of gas produced when 120g of marble, containing 10% impurities, is treated with hydrochloric acid, given that the product yield is 90%.

Solution:

First, let's calculate the mass of pure marble: - Mass of impurities = 120g * 10% = 12g - Mass of pure marble = 120g - 12g = 108g

Now, we need to find the molar mass of calcium carbonate (marble) and the balanced chemical equation for the reaction between calcium carbonate and hydrochloric acid.

The balanced chemical equation for the reaction is: CaCO3(s) + 2HCl(aq) → CaCl2(aq) + H2O(l) + CO2(g)

From the balanced chemical equation, we can see that 1 mole of calcium carbonate produces 1 mole of carbon dioxide gas.

Next, we calculate the number of moles of calcium carbonate: - Moles of CaCO3 = Mass of CaCO3 / Molar mass of CaCO3 - Molar mass of CaCO3 = 40.08 (Ca) + 12.01 (C) + 3 * 16.00 (O) = 100.09 g/mol - Moles of CaCO3 = 108g / 100.09 g/mol

Now, we calculate the volume of carbon dioxide gas produced using the ideal gas law: PV = nRT Where: - P = pressure (assume standard pressure, 1 atm) - V = volume of gas - n = number of moles of gas - R = ideal gas constant (0.0821 L·atm/(K·mol)) - T = temperature (assume standard temperature, 273 K)

Rearranging the ideal gas law to solve for V: V = (nRT) / P

Given that the product yield is 90%, we can calculate the moles of carbon dioxide gas produced: - Moles of CO2 produced = Moles of CaCO3 * 1 (from the balanced equation) * 90%

Finally, we can calculate the volume of carbon dioxide gas produced using the ideal gas law.

Let's calculate the volume of gas produced using the above steps.