Question

Закінчити рiвняння реакцій та розставити коефіцієнти 1.CaO+H₂O= 2. CO2+ H2O =3. Al203+ SO3=4. BaO + HCL=5. KOH + HNO3=6.NaOH-ALCL3= 7. Ca(OH)2+CO2=8. Zn(OH)2=9. BaO+H2O=10. Fe(OH)2+ H₂SO4=11. Na2O + H2О=12. FeO+SO2=​

Answer 1

Ответ:

1. Ca(OH)2

2. H2CO3

3. Ale(SO4) 3

4. BaCl2+H2O

5. КNO3+H20

6. 3NaCl+Al(OH)3

7. CaCO3+H2O

8.?

9. Ba(OH)2

10. FeSo4+2H2

11. 2NaOH

12. FeSO3

Answer 2

Balancing Chemical Equations:

1. CaO + H₂O = Ca(OH)₂ - Calcium oxide (CaO) reacts with water (H₂O) to form calcium hydroxide (Ca(OH)₂. - Balanced equation: CaO + H₂O = Ca(OH)₂ [[1]].

2. CO₂ + H₂O = H₂CO₃ - Carbon dioxide (CO₂) reacts with water (H₂O) to form carbonic acid (H₂CO₃). - Balanced equation: CO₂ + H₂O = H₂CO₃ [[2]].

3. Al₂O₃ + SO₃ = Al₂(SO₄)₃ - Aluminum oxide (Al₂O₃) reacts with sulfur trioxide (SO₃) to form aluminum sulfate (Al₂(SO₄)₃). - Balanced equation: Al₂O₃ + SO₃ = Al₂(SO₄)₃ [[3]].

4. BaO + HCl = BaCl₂ + H₂O - Barium oxide (BaO) reacts with hydrochloric acid (HCl) to form barium chloride (BaCl₂) and water (H₂O). - Balanced equation: BaO + 2HCl = BaCl₂ + H₂O [[4]].

5. KOH + HNO₃ = KNO₃ + H₂O - Potassium hydroxide (KOH) reacts with nitric acid (HNO₃) to form potassium nitrate (KNO₃) and water (H₂O). - Balanced equation: KOH + HNO₃ = KNO₃ + H₂O [[5]].

6. NaOH + AlCl₃ = NaCl + Al(OH)₃ - Sodium hydroxide (NaOH) reacts with aluminum chloride (AlCl₃) to form sodium chloride (NaCl) and aluminum hydroxide (Al(OH)₃). - Balanced equation: 3NaOH + AlCl₃ = 3NaCl + Al(OH)₃ [[6]].

7. Ca(OH)₂ + CO₂ = CaCO₃ + H₂O - Calcium hydroxide (Ca(OH)₂) reacts with carbon dioxide (CO₂) to form calcium carbonate (CaCO₃) and water (H₂O). - Balanced equation: Ca(OH)₂ + CO₂ = CaCO₃ + H₂O [[7]].

8. Zn(OH)₂ = ZnO + H₂O - Zinc hydroxide (Zn(OH)₂) decomposes into zinc oxide (ZnO) and water (H₂O). - Balanced equation: Zn(OH)₂ = ZnO + H₂O [[8]].

9. BaO + H₂O = Ba(OH)₂ - Barium oxide (BaO) reacts with water (H₂O) to form barium hydroxide (Ba(OH)₂). - Balanced equation: BaO + H₂O = Ba(OH)₂ [[9]].

10. Fe(OH)₂ + H₂SO₄ = FeSO₄ + 2H₂O - Iron(II) hydroxide (Fe(OH)₂) reacts with sulfuric acid (H₂SO₄) to form iron(II) sulfate (FeSO₄) and water (H₂O). - Balanced equation: Fe(OH)₂ + H₂SO₄ = FeSO₄ + 2H₂O [[10]].

11. Na₂O + H₂O = 2NaOH - Sodium oxide (Na₂O) reacts with water (H₂O) to form sodium hydroxide (NaOH). - Balanced equation: Na₂O + H₂O = 2NaOH [[11]].

12. FeO + SO₂ = FeSO₃ - Iron(II) oxide (FeO) reacts with sulfur dioxide (SO₂) to form iron(II) sulfate (FeSO₃). - Balanced equation: FeO + SO₂ = FeSO₃ [[12]].

Please note that these balanced equations are based on the information provided and may vary depending on specific reaction conditions.