Question

M (Fe203) = 320 г + Hcl M(FeCl3) -?

Answer 1

Ответ:

Масса хлорида железа (III) равна = 650 г.

Объяснение:

Дано:

m(Fe2O3) = 320 г.

Найти:

m(Fecl3) -?

Решение:

Составим УХР по условию задачи:

• Fe2O3 + 6HCl = 2FeCl3 + 3H2O

Найдем количество вещества оксида железа (III) по формуле:

n(в-ва) = m(в-ва) / M(в-ва)

• n(Fe2O3) = 320 г. / 160 г/моль = 2 моль
• n(Fe2O3) = 320 г. / 160 г/моль = 2 мольM(Fe2O3) = 160 г/моль

Составим пропорцию по УХР для нахождения количества вещества хлорида железа (III):

• n(Fe2O3) = 2n(FeCl3), n(FeCl3) = 4 моль

Найдем массу хлорида железа (III) по формуле:

m(в-ва) = n(в-ва) * M(в-ва)

• m(FeCl3) = 4 моль * 162,5 г/моль = 650 г.

Answer 2

To determine the amount of FeCl3 formed when 320g of Fe2O3 reacts with HCl, we need to consider the balanced chemical equation for the reaction:

Fe2O3 + 6HCl → 2FeCl3 + 3H2O

According to the equation, one mole of Fe2O3 reacts with 6 moles of HCl to produce 2 moles of FeCl3. To find the amount of FeCl3 formed, we'll follow these steps:

Step 1: Calculate the number of moles of Fe2O3.

• Molar mass of Fe2O3 = 2 * atomic mass of Fe + 3 * atomic mass of O = 2 * 55.845 g/mol + 3 * 16.00 g/mol = 159.69 g/mol

• Moles of Fe2O3 = mass of Fe2O3 / molar mass of Fe2O3 = 320 g / 159.69 g/mol ≈ 2.00 mol (approximately)

Step 2: Use the mole ratio to find moles of FeCl3.

• From the balanced equation, we know that 1 mole of Fe2O3 reacts to form 2 moles of FeCl3.

• Moles of FeCl3 = 2 * moles of Fe2O3 = 2 * 2.00 mol = 4.00 mol

Step 3: Convert moles of FeCl3 to grams.

• Molar mass of FeCl3 = atomic mass of Fe + 3 * atomic mass of Cl = 55.845 g/mol + 3 * 35.453 g/mol = 162.204 g/mol

• Mass of FeCl3 = moles of FeCl3 * molar mass of FeCl3 = 4.00 mol * 162.204 g/mol ≈ 648.816 g (approximately)

Therefore, approximately 648.816 grams of FeCl3 would be formed when 320 grams of Fe2O3 reacts with HCl.