Question

11. Al(OH)3 → Al2O3 + H2O 12. Au2O3 + H2 → Au + H2O

Answer 1

Ответ:

2Al(OH)₃ → Al₂O₃ + 3H₂O - разложение

Au₂O₃ + 3H₂ → 2Au + 3H₂O -замещение

сложные вещества:

Al(OH)₃ - гидроксид алюминия

Al₂O₃ -оксид алюминия

H₂O  -оксид водорода (вода)

Answer 2

The two equations you provided are balanced chemical equations representing chemical reactions. Let's examine each equation individually:

11. Al(OH)3 → Al2O3 + H2O

This equation represents the decomposition of aluminum hydroxide (Al(OH)3) into aluminum oxide (Al2O3) and water (H2O). To balance the equation, we need to ensure that there is an equal number of atoms on both sides. Here is the balanced equation:

2 Al(OH)3 → Al2O3 + 3 H2O

This means that when two moles of aluminum hydroxide decompose, they produce one mole of aluminum oxide and three moles of water.

12. Au2O3 + H2 → Au + H2O

This equation represents the reduction of gold(III) oxide (Au2O3) with hydrogen gas (H2) to produce gold metal (Au) and water (H2O). Let's balance the equation:

Au2O3 + 3 H2 → 2 Au + 3 H2O

In this balanced equation, one mole of gold(III) oxide reacts with three moles of hydrogen gas to yield two moles of gold and three moles of water.

Please note that the coefficients in front of the chemical formulas represent the stoichiometric ratios and are used to balance the equation, ensuring the conservation of mass and atoms in a chemical reaction.