Question

С2Н4 → С2Н5Сl → С2Н5ОН → С2Н4 → СO2;

Answer 1

C2H4 + HCL = C2H5CL
C2H5CL + KOH = C2H5OH + KCL
C2H5OH = C2H4 + H2O
C2H4 +3O2 =2CO2 +2H2O

Answer 2

C2H4+Cl2=C2H5Cl+HCl
C2H5Cl+NaOH=NaCl+C2H5OH
C2H5OH=(t>150°C)C2H4+H2O
C2H4+2,5O2=2CO2+2H2O

Answer 3

The chemical reactions you've provided involve the conversion of ethylene (C2H4) into ethyl chloride (C2H5Cl), then into ethanol (C2H5OH), and finally back into ethylene (C2H4). The last step you've mentioned is the combustion of ethylene, resulting in carbon dioxide (CO2).

Here's a breakdown of the reactions:

1. C2H4 (ethylene) reacts with HCl (hydrochloric acid) to form C2H5Cl (ethyl chloride). C2H4 + HCl → C2H5Cl

2. C2H5Cl (ethyl chloride) reacts with NaOH (sodium hydroxide) to form C2H5OH (ethanol) and NaCl (sodium chloride). C2H5Cl + NaOH → C2H5OH + NaCl

3. C2H5OH (ethanol) can be dehydrated (removal of water) to produce C2H4 (ethylene). C2H5OH → C2H4 + H2O

4. Finally, C2H4 (ethylene) can undergo combustion to produce CO2 (carbon dioxide) and H2O (water). C2H4 + O2 → CO2 + H2O

It's important to note that these reactions are simplified and might not include specific reaction conditions or catalysts that could be required in reality. Additionally, reaction yields and side reactions may vary depending on the specific experimental conditions.