Question

Определить степень окисления: Be(OH)2 , H2CO3 , NaNo3 , CO2 , FeO

Answer 1

Be⁺² (O⁻² H⁺¹ )2 , H⁺¹ 2C⁺⁴ O⁻² 3 , Na⁺¹ N⁺⁵ o⁻² 3 , C⁺⁴ O⁻² 2 , Fe⁺² O⁻²

Answer 2

1. Be(OH)2: Be has a +2 oxidation state, and the overall molecule has no charge. The oxidation state of O is -2, and the oxidation state of H is +1.

Therefore, the oxidation state of Be in Be(OH)2 is +2, the oxidation state of O in OH is -2, and the oxidation state of H in OH is +1.

2. H2CO3: Carbonate ion (CO3^-2) has an overall charge of -2, and two H+ ions are needed to balance this charge.

The oxidation state of H in H2CO3 is +1, and the oxidation state of O in CO3^-2 is -2.

Therefore, the oxidation state of C in H2CO3 is +4.

3. NaNO3: Na+ has a +1 oxidation state, and NO3^- has an overall charge of -1. The oxidation state of O is -2.

Therefore, the oxidation state of N in NO3^- is +5, and the oxidation state of O in NO3^- is -2.

4. CO2: Oxygen atoms in CO2 have an oxidation state of -2.

Therefore, the oxidation state of C in CO2 is +4.

5. FeO: Oxygen atoms in FeO have an oxidation state of -2.

Therefore, the oxidation state of Fe in FeO is +2.