Question

M(C2H2)= 56 г V(C2H2)-?

Answer 1

M(C2H2)=26 г/моль

Vm=22,4 л/моль

n(C2H2)=m/M=56/26=2,1 моль

V(C2H2)=Vm*n=22,4*2,1=47 л

Answer 2

To calculate the volume of acetylene gas (C2H2), we need to use the ideal gas law equation:

PV = nRT

where P is the pressure of the gas, V is its volume, n is the number of moles of gas, R is the gas constant, and T is the temperature in Kelvin.

We can rearrange this equation to solve for V:

V = nRT/P

First, we need to determine the number of moles of C2H2 gas. We know that the molar mass of C2H2 is 26 g/mol + 2(1 g/mol) = 26 + 2 = 28 g/mol.

So, the number of moles of C2H2 can be calculated as follows:

n = m/M = 56 g / 28 g/mol = 2 mol

Next, we need to determine the pressure, temperature, and gas constant.

Assuming standard temperature and pressure (STP), which is defined as 0°C (273.15 K) and 1 atmosphere (1 atm), respectively, the pressure is:

P = 1 atm

The gas constant is:

R = 0.0821 L·atm/(mol·K)

Now we can substitute these values into the equation for V:

V = nRT/P = (2 mol)(0.0821 L·atm/(mol·K))(273.15 K) / (1 atm)

Solving this equation, we get:

V = 44.8 L

Therefore, the volume of acetylene gas (C2H2) at STP is approximately 44.8 liters.