Question

Решите 7 номер пожалуйста умоляю помогите

Answer 1

A
{36x+12-36x-27≥3x⇒3x≤-15⇒x≤-5
{(x-2)(x+9)<0   x=2  x=-9   ⇒-9<x<2
       //////////////////////////////////////
-----(9)-----------[-5]------------(2)-----------
//////////////////////////
x∈(-9;-5]
б
{(10-2x)/[3+(5-2x)²] 3+(5-2x)²>0⇒10-2x≥0⇒2x≤10⇒x≤5
{2-7x≤14-3x⇒-7x+3x≤14-2⇒-4x≤12⇒x≥-3
                ////////////////////////////////////////////////////////
------------[-3]---------------------------{5]--------------
\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\
x∈[-3;5]
в
{(24-3x)/[8+(5-2x)²]≥0 ,8+(5-2x)²>0⇒24-3x≥0⇒24-3x≥0⇒x≤8
{-9x+2x≤43-22⇒-7x≤21⇒x≥-3
\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\
---------[-3]--------------------------[8]-----------
            \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\
x∈[-3;8]