Question

Поезд прошел первый перегон за 2 часа, а второй за 3часа.Всего за это время он прошел расстояние 330км.Найдите скорость поезда на каждом перегоне,если на втором,перегоне она была на 10км/ч больше,чем на первом.

Answer 1

х - км/ч - скорость на 1-ом перегоне

х+10 км/ч - скорость на 2-ом перегоне

х * 2 + 3*( х+10)=330

2х + 3х + 30=330

5х = 300

х= 60 км/ч - скорость на 1-ом перегоне

60+10=70 км/ч скорость на 2-ом перегоне

Проверка:

60*2 + 70*3 = 120+210=330км

Answer 2

Problem Analysis

We are given that a train traveled a total distance of 330 km, with the first leg taking 2 hours and the second leg taking 3 hours. The speed of the train on the second leg was 10 km/h faster than on the first leg. We need to find the speed of the train on each leg.

Solution

Let's assume the speed of the train on the first leg is x km/h. Since the speed on the second leg is 10 km/h faster, the speed on the second leg is x + 10 km/h.

We can use the formula speed = distance / time to find the speed on each leg.

# Speed on the First Leg

The distance traveled on the first leg is not given directly, but we can calculate it using the formula distance = speed * time. Substituting the values we have, we get:

distance on the first leg = speed on the first leg * time on the first leg = x * 2

# Speed on the Second Leg

Similarly, we can calculate the distance traveled on the second leg:

distance on the second leg = speed on the second leg * time on the second leg = (x + 10) * 3

Since the total distance traveled is 330 km, we can write the equation:

distance on the first leg + distance on the second leg = 330

Substituting the calculated distances, we get:

x * 2 + (x + 10) * 3 = 330

Now we can solve this equation to find the value of x.

Calculation

Let's solve the equation:

2x + 3(x + 10) = 330

Simplifying the equation:

2x + 3x + 30 = 330

5x + 30 = 330

5x = 300

x = 60

The speed on the first leg is 60 km/h.

Since the speed on the second leg is 10 km/h faster, the speed on the second leg is 60 + 10 = 70 km/h.

Answer

The speed of the train on the first leg is 60 km/h, and the speed on the second leg is 70 km/h.

Please let me know if I can help you with anything else.