
Из двух портов вышли одновременно навстречу друг другу два рыболовных судна траулер и сейнер.
Траулер шёл со скоростью 25 км / ч и через 5 ч встретился с сейнером. Найди расстояние между портами если скорость сейнера составляет 4/5 скорости траулера.

Ответы на вопрос

25*5=125 км прошол траул
25*4\5=20 км в час шол сейн
20*5+125=225 км расст между портами



Calculation of the Distance between Ports
To find the distance between the two ports, we can use the formula:
Distance = Speed x Time
Given that the trawler's speed is 25 km/h and it took 5 hours for the trawler to meet the seiner, we can calculate the distance traveled by the trawler:
Distance_trawler = Speed_trawler x Time = 25 km/h x 5 h = 125 km .
Since the seiner's speed is 4/5 of the trawler's speed, we can calculate the distance traveled by the seiner:
Speed_seiner = 4/5 x Speed_trawler = 4/5 x 25 km/h = 20 km/h
Now, let's assume that the distance between the two ports is D km.
The trawler traveled 125 km to meet the seiner, which means that the remaining distance for the seiner to reach the port is D - 125 km.
To find the time it took for the seiner to cover this remaining distance, we can use the formula:
Time_seiner = Distance_seiner / Speed_seiner
Substituting the values, we have:
Time_seiner = (D - 125 km) / 20 km/h
Since both the trawler and the seiner started from their respective ports at the same time, the total time taken by both ships to meet each other is 5 hours.
Therefore, we can write the equation:
Time_trawler + Time_seiner = 5 hours
Substituting the values, we have:
5 hours = 5 hours
Now, we can solve for D by substituting the values of Time_seiner and Speed_seiner:
(D - 125 km) / 20 km/h + 5 hours = 5 hours
Simplifying the equation, we have:
(D - 125 km) / 20 km/h = 0
Multiplying both sides by 20 km/h, we get:
D - 125 km = 0
Adding 125 km to both sides, we have:
D = 125 km
Therefore, the distance between the two ports is 125 km.
Please note that the calculation assumes constant speeds for both ships and a linear path between the ports.


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