Question

Литр одного раствора содержит 20 гр. соли, литр другого раствора -втрое больше. смешали 5 литров первого раствора и 3 литра второго. Сколько граммов соли содержится в новом растворе?

Answer 1

) 20*3=60грамм во втором растворе
2) 20*5=100грамм в 5 литрах первого раствора
3) 6083=180грамм в 3 литраз второго раствора
4) 100+180=280 грамм соли в 8 литрах нового раствора
5) 280:8=35грамм соли в 1 литре полученного раствора
 Вот и всё!

Answer 2

Calculation of Salt Content in the New Solution

To calculate the amount of salt in the new solution, we need to consider the concentration of salt in each of the two original solutions and the volumes of these solutions that were mixed together.

Let's denote the concentration of salt in the first solution as C1 (20 grams per liter) and the concentration of salt in the second solution as C2 (three times the concentration of the first solution, or 60 grams per liter).

The volume of the first solution that was mixed is 5 liters, and the volume of the second solution is 3 liters.

To find the total amount of salt in the new solution, we can use the following formula:

Total salt content = (C1 * V1) + (C2 * V2)

Where: - C1 is the concentration of salt in the first solution (20 grams per liter) - V1 is the volume of the first solution (5 liters) - C2 is the concentration of salt in the second solution (60 grams per liter) - V2 is the volume of the second solution (3 liters)

Let's substitute the values into the formula and calculate the total salt content in the new solution:

Total salt content = (20 * 5) + (60 * 3)

Total salt content = 100 + 180

Total salt content = 280 grams

Therefore, the new solution contains 280 grams of salt.