Question

В результате ошибки, при комплектовании составов пассажирских поездов один состав оказался в полтора раза длиннее другого. Чтобы уравнять число вагонов в обоих поездах, от первого состава отцепили 4 вагона и прицепили их ко второму составу. Сколько вагонов было в каждом составе первоначально?

Answer 1

1,5х - первый состав
х - второй состав
1,5х-4=х+4
1,5х-х=4+4
0,5х=8
х=8:0,5
х=16 вагонов - было во втором
16*1,5=24 вагона - в первом

Answer 2

Problem Analysis

We are given that there was an error in the composition of passenger train sets, resulting in one set being one and a half times longer than the other. To equalize the number of cars in both sets, 4 cars were detached from the longer set and attached to the shorter set. We need to determine the initial number of cars in each set.

Solution

Let's assume that the initial number of cars in the shorter set is x. Since the longer set is one and a half times longer, the initial number of cars in the longer set would be 1.5x.

To equalize the number of cars, 4 cars were detached from the longer set and attached to the shorter set. After this adjustment, the number of cars in the shorter set would be x + 4, and the number of cars in the longer set would be 1.5x - 4.

To find the initial number of cars in each set, we need to solve the following equations simultaneously:

1. x + 4 (number of cars in the shorter set after adjustment) 2. 1.5x - 4 (number of cars in the longer set after adjustment)

Let's solve these equations:

x + 4 = 1.5x - 4

Simplifying the equation:

2x = 8

Dividing both sides by 2:

x = 4

Therefore, the initial number of cars in the shorter set was 4, and the initial number of cars in the longer set was 1.5x = 1.5 * 4 = 6.

Answer

The initial number of cars in each set was: - Shorter set: 4 cars - Longer set: 6 cars