Question

Два велосипедиста выехали одновременно навстречу друг другу из пунктов а и б расстояние между которыми 30 км и встретелись через 1 час Найдите скорость каждого велосипедиста если скорость одного из них на 2 км\ч больше скорости другого

Answer 1

Пусть х км/ч - скорость одного, х + 2 км/ч - скорость другого, тогда х + х + 2 км/ч - скорость сближения
Составим уравнение и решим его:
х + х + 2 * 1 = 30
2х + 2 = 30
2х = 30 - 2
2х = 28
х = 28 : 2
х = 14 (км/ч) - скорость одного
2 + 14 = 16 (км/ч) - скорость другого
Ответ: 14 км/ч и 16 км/ч

Answer 2

Problem Analysis

We are given that two cyclists start simultaneously from points A and B, which are 30 km apart. They meet after 1 hour. We need to find the speed of each cyclist, given that one cyclist's speed is 2 km/h faster than the other.

Solution

Let's assume the speed of one cyclist is x km/h. Then the speed of the other cyclist will be (x + 2) km/h.

We can use the formula distance = speed × time to find the distance traveled by each cyclist in 1 hour.

For the cyclist with speed x km/h: - Distance traveled = x km/h × 1 hour = x km

For the cyclist with speed (x + 2) km/h: - Distance traveled = (x + 2) km/h × 1 hour = (x + 2) km

Since the total distance between the two cyclists is 30 km, we can set up the following equation:

x km + (x + 2) km = 30 km

Simplifying the equation:

2x + 2 = 30 2x = 28 x = 14

Therefore, one cyclist's speed is 14 km/h, and the other cyclist's speed is 16 km/h.

Answer

The speed of the first cyclist is 14 km/h, and the speed of the second cyclist is 16 km/h.