Вопрос задан 13.01.2020 в 02:51. Предмет Математика. Спрашивает Резнов Антон.

Бабушке 80 лет. Возраст мамы составляет 5/8 возраста бабушки, а возраст сына состовляет2/5 возраста

мамы. Сколько лет сыну? ====================================================================== Для трёх новых домох приготовили 1208 дверей.В первый дом поставили 1/4 всех дверей, во второй дом - на 124 двери больше. Сколько дверей поставили в третий дом? ====================================================================== Фабрика выпустила 5124 пальто, кастюмов и платьев. Пальто состовляет 2/7 всех вещей, костюмов было 2 раза больше, чем пальто. Сколько платьев выпустила фабрика?
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Отвечает Дунаева Александра.
Сыну 20 лет
480 дверей
732 платьев
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Отвечает нейросеть ChatGpt. Будьте внимательны, ответы нейросети могут содержать ошибочные или выдуманные данные.

Answer:

Question 1: To find the age of the son, we need to determine the ages of the grandmother and the mother first. Let's assume the age of the grandmother is G, the age of the mother is M, and the age of the son is S.

According to the given information: - The age of the mother (M) is 5/8 of the age of the grandmother (G). - The age of the son (S) is 2/5 of the age of the mother (M).

We can set up the following equations: 1. M = (5/8) * G 2. S = (2/5) * M

To solve this system of equations, we can substitute the value of M from equation 1 into equation 2: S = (2/5) * ((5/8) * G)

Simplifying the equation: S = (1/4) * G

Since the grandmother is 80 years old, we can substitute G = 80 into the equation to find the age of the son: S = (1/4) * 80 S = 20

Therefore, the son is 20 years old.

Question 2: Let's assume the number of doors in the first house is D1, the number of doors in the second house is D2, and the number of doors in the third house is D3.

According to the given information: - The number of doors in the first house (D1) is 1/4 of the total number of doors. - The number of doors in the second house (D2) is 124 more than the number of doors in the first house (D1). - The total number of doors in the three houses is 1208.

We can set up the following equations: 1. D1 + D2 + D3 = 1208 2. D1 = (1/4) * (D1 + D2 + D3) 3. D2 = D1 + 124

To solve this system of equations, we can substitute the value of D1 from equation 2 into equations 1 and 3: (1/4) * (D1 + D2 + D3) + D2 + D3 = 1208 D1 + 124 = D1 + D2 + D3

Simplifying the equations: (1/4) * (D1 + D2 + D3) + D2 + D3 = 1208 D2 + D3 = 984

D1 + 124 = D1 + D2 + D3 124 = D2 + D3

Substituting the value of D2 + D3 from the second equation into the first equation: D2 + D3 = 984 124 = 984

This is not possible, as 124 is not equal to 984. There seems to be an error in the given information or calculations.

Question 3: Let's assume the number of coats is C, the number of suits is S, and the number of dresses is D.

According to the given information: - The number of coats (C) is 2/7 of the total number of items. - The number of suits (S) is twice the number of coats (C). - The total number of coats, suits, and dresses is 5124.

We can set up the following equations: 1. C + S + D = 5124 2. C = (2/7) * (C + S + D) 3. S = 2 * C

To solve this system of equations, we can substitute the value of C from equation 2 into equations 1 and 3: (2/7) * (C + S + D) + S + D = 5124 2 * C = S

Simplifying the equations: (2/7) * (C + S + D) + S + D = 5124 2 * C = S

Substituting the value of S from the third equation into the first equation: (2/7) * (C + 2 * C + D) + 2 * C + D = 5124 (2/7) * (3 * C + D) + 2 * C + D = 5124

Simplifying the equation: (6/7) * C + (2/7) * D + 2 * C + D = 5124 (20/7) * C + (9/7) * D = 5124

Since the number of coats, suits, and dresses is 5124, we can substitute C + S + D = 5124 into the equation: (20/7) * C + (9/7) * D = 5124

Unfortunately, we cannot determine the exact number of dresses without additional information or constraints. The given information is insufficient to find the number of dresses.

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