Question

Помогите решить двумя способами задачу, дам 30 бал. У Каплауха в три раза больше орехов,чем у его подружки белочке. Они сложили все орехи, поделили поровну. и съели их.Сколько орехов было сначала у каждого из них, если они съели по 12 орехов?

Answer 1

Всего орехов было 12×2=24 от
у К -3 части
У белочки -1 часть
всего 3+1=4 части
24÷4=6- было у белочки
6×3=18 было у каплауха

Answer 2

Problem Analysis

To solve this problem, we need to find the initial number of nuts that Kaplauha and his friend, the squirrel, had before they shared and ate them. We know that Kaplauha had three times more nuts than the squirrel. We also know that they shared the nuts equally and ate 12 nuts each. Let's solve this problem step by step.

Solution 1: Using Algebra

Let's assume that the number of nuts the squirrel had initially is x. According to the problem, Kaplauha had three times more nuts than the squirrel, so he had 3x nuts.

When they shared the nuts equally, the total number of nuts they had is the sum of the nuts each of them had initially: x + 3x = 4x

Since they ate 12 nuts each, the remaining number of nuts is: 4x - 12 - 12 = 4x - 24

Since they shared the remaining nuts equally, we can set up the equation: (4x - 24) / 2 = 12

Now, let's solve this equation to find the value of x:

(4x - 24) / 2 = 12
4x - 24 = 2 * 12
4x - 24 = 24
4x = 24 + 24
4x = 48
x = 48 / 4
x = 12

Therefore, the squirrel initially had 12 nuts, and Kaplauha had 3x = 3 * 12 = 36 nuts.

Solution 2: Using Trial and Error

Another way to solve this problem is by using trial and error. We can start with different numbers of nuts for the squirrel and check if the conditions of the problem are satisfied.

Let's assume the squirrel initially had 10 nuts. Then Kaplauha would have 3 * 10 = 30 nuts.

When they shared the nuts equally, the total number of nuts they had is: 10 + 30 = 40

Since they ate 12 nuts each, the remaining number of nuts is: 40 - 12 - 12 = 16

If they shared the remaining nuts equally, each of them would have 16 / 2 = 8 nuts. But this doesn't match the problem's condition, as they should have had 12 nuts each.

Let's try another assumption. Let's assume the squirrel initially had 12 nuts. Then Kaplauha would have 3 * 12 = 36 nuts.

When they shared the nuts equally, the total number of nuts they had is: 12 + 36 = 48

Since they ate 12 nuts each, the remaining number of nuts is: 48 - 12 - 12 = 24

If they shared the remaining nuts equally, each of them would have 24 / 2 = 12 nuts. This matches the problem's condition.

Therefore, the squirrel initially had 12 nuts, and Kaplauha had 3 * 12 = 36 nuts.

Conclusion

In conclusion, there are two possible solutions to the problem: - Solution 1: The squirrel initially had 12 nuts, and Kaplauha had 36 nuts. - Solution 2: The squirrel initially had 12 nuts, and Kaplauha had 36 nuts.

Both solutions satisfy the conditions of the problem, and in both cases, they would have shared and eaten 12 nuts each.

Please let me know if you need any further assistance!