Question

Два велосипедиста одновременно выехали друг другу навстречу из пунктов А и В ,расстояние межжду которым 66км. Скорость одного 12км/чЭ а другого на 2 км/ч меньше. Сколько км останется проехать им до встречи , если после их выезда прошло 2 часа ?

Answer 1

Скорость 2-ого велосипедиста 12-2=10(км/ч)
66-(12*2+10*2)=22(км)

Answer 2

12-2=10км/ч - скорость другого велосипедиста

12*2=24км - проехал первый велосипедист

10*2=20км-проехал другой велосипедист

66-24-20=22км осталось до встречи

Ответ: 22км

Answer 3

Problem Analysis

Two cyclists start simultaneously from points A and B, which are 66 km apart. One cyclist has a speed of 12 km/h, while the other has a speed 2 km/h slower. We need to determine how many kilometers they have left to travel until they meet, given that 2 hours have passed since they started.

Solution

To solve this problem, we can use the formula: distance = speed × time.

Let's denote the distance traveled by the first cyclist as x km. Since the second cyclist is traveling at a speed 2 km/h slower, their speed is 12 - 2 = 10 km/h.

The time traveled by both cyclists is 2 hours. Therefore, the distance traveled by the first cyclist is 12 × 2 = 24 km.

The remaining distance between the two cyclists is 66 - 24 = 42 km.

Therefore, the two cyclists have 42 km left to travel until they meet.

Answer

The two cyclists have 42 km left to travel until they meet.