Question

Первый мастер за день зделал 25 деталей а второй 29 таких самых деталей. Первый заработал за етот день на 40 грн менше чем второй. Сколько гривен зароботает каждый мастер за месяц (20 робочех дней ) если будут роботать з етойже продуктивностей РЕШЫТЕ ПОЖАЛУЙСТА ДЕЙСТВИЯМИ ИЛИ РАВЕНСТВАМ СРОЧНО ОЧЕНЬ

Answer 1

1) 29-25=4 (дет.) - на сколько деталей второй мастер сделал больше, чем первый
2) 40:4 = 10(грн.) - цена одной детали.
3) 25х20=500 (дет.) - делает первый мастер за рабочий месяц
4) 29х20=580 (дет.) - делает второй мастер за рабочий месяц
5) 500х10=5000(грн) - заработает первый мастер за рабочий месяц
6) 580х10= 5800 (грн) - заработает второй мастер за рабочий месяц

Answer 2

Problem Analysis

We are given that the first master made 25 pieces in a day and the second master made 29 pieces in the same day. The first master earned 40 UAH less than the second master. We need to calculate how much each master will earn in a month if they work with the same productivity for 20 working days.

Solution

Let's denote the earnings of the first master as x UAH and the earnings of the second master as y UAH.

From the given information, we can set up the following equations:

1. The first master made 25 pieces in a day: - The first master's productivity is 25 pieces per day. - The first master's earnings per day can be calculated as x / 25 UAH per piece.

2. The second master made 29 pieces in a day: - The second master's productivity is 29 pieces per day. - The second master's earnings per day can be calculated as y / 29 UAH per piece.

3. The first master earned 40 UAH less than the second master: - The first master's earnings per day is x / 25 UAH per piece. - The second master's earnings per day is y / 29 UAH per piece. - So, we can set up the equation: x / 25 = y / 29 - 40.

4. We need to calculate how much each master will earn in a month (20 working days): - The first master's earnings in a month can be calculated as 20 * (x / 25) UAH. - The second master's earnings in a month can be calculated as 20 * (y / 29) UAH.

To solve this system of equations, we can substitute the value of x from equation 3 into equations 4 to find the values of y and the earnings of each master.

Let's solve the equations step by step:

Solution Steps

1. From equation 3, we have x / 25 = y / 29 - 40. 2. Rearranging the equation, we get x = (25y / 29) - 1000. 3. Substituting the value of x in equation 4, we have: - The first master's earnings in a month: 20 * ((25y / 29) - 1000) / 25 UAH. - The second master's earnings in a month: 20 * (y / 29) UAH.

Let's calculate the earnings of each master in a month:

Calculation

1. The first master's earnings in a month: - 20 * ((25y / 29) - 1000) / 25 UAH. - Simplifying the expression, we get: 20 * (y / 29) - 20000 UAH.

2. The second master's earnings in a month: - 20 * (y / 29) UAH.

Therefore, the first master will earn 20 * (y / 29) - 20000 UAH in a month, and the second master will earn 20 * (y / 29) UAH in a month.

Please note that we need the value of y to calculate the exact earnings of each master. Unfortunately, the value of y is not provided in the given information. If you can provide the value of y, I can calculate the earnings of each master in a month.