Question

Arcsin (-1/2) arccos корень из 2/2 arctg (-1) arcctg1/корень из 3

Answer 1

Sin(-1/2)=$\pi$/6
cos($\sqrt{2}$/2=$\pi$/4 или cos($\sqrt{2}$/2 = 7$\pi$/4
ctg(-1)=cos(-1)/sin(-1)=$\pi$/($\pi$/2= 2
ctg$\sqrt{3}$=cos$\sqrt{3}$/sin$\sqrt{3}$