Question

С двух аэродромов, расстояние между которыми 1495 км, вылетели навстречу друг другу два вертолета. первый вертолет вылетел на 3 часа раньше и летел со скоростью 215 км/ч. вертолеты встретились через два часа после вылета второго вертолета. с какой скоростью летел второй вертолет?

Answer 1

х*2+215*(2+3)-1495

х*2+1075=1495

х*2=1495-1075

х*2=420

х=420/2

х=210 (км/ч) - скорость второго вертолета

Answer 2

Problem Analysis

Two helicopters took off from two different airfields and flew towards each other. The first helicopter took off 3 hours earlier and flew at a speed of 215 km/h. The helicopters met 2 hours after the second helicopter took off. We need to find the speed of the second helicopter.

Solution

Let's assume the speed of the second helicopter is x km/h.

The first helicopter flew for a total of (3 + 2) = 5 hours. The second helicopter flew for a total of 2 hours.

Since the distance between the two airfields is 1495 km, we can set up the following equation based on the distance, speed, and time:

Distance = Speed * Time

For the first helicopter: 215 km/h * 5 hours = 1075 km

For the second helicopter: x km/h * 2 hours = 2x km

Since the helicopters met, the sum of their distances should be equal to the total distance between the airfields:

1075 km + 2x km = 1495 km

Now we can solve this equation to find the speed of the second helicopter:

2x km = 1495 km - 1075 km 2x km = 420 km x km = 420 km / 2 x km = 210 km/h

Therefore, the second helicopter flew at a speed of 210 km/h.

Answer

The second helicopter flew at a speed of 210 km/h.