Question

Сколько нулей стоит в конце произведения всех натуральных чисел от 9 до 29?

Answer 1

Нужно 10 разложить на множители
10= 5*2
двоек в ряду последовательных чисел больше 5. Значит до 29 нужно 5 нулей,т.к 25=5*5

Answer 2

1.колличество нулей в конце зависит от того сколько 10 в множителях.
2.разложим 10 на простые множители  10=2*5
3.двоек в ряду последовательных чисел больше 5 , значит посчитаем 5, от 9 до 29 (5 пятерок: 10;15:20;25) , а 5 т.к. 25=5*5 ,т.е. считаем ее два раза 
 4.ответ 5 нулей

Answer 3

Number of Zeros at the End of the Product

To find the number of zeros at the end of the product of all natural numbers from 9 to 29, we need to determine the number of factors of 10 in the product. This is because a factor of 10 is formed by multiplying 2 and 5, and since 2 is more abundant than 5 in the given range, we only need to count the number of factors of 5.

To calculate the number of factors of 5, we can count the number of multiples of 5 in the given range and then add the number of multiples of 25, as each multiple of 25 contributes an additional factor of 5.

Let's calculate the number of factors of 5 in the given range:

- Multiples of 5: 10, 15, 20, 25 - Multiples of 25: 25

Therefore, there are a total of 5 factors of 5 in the product of all natural numbers from 9 to 29.

Since each factor of 5 contributes a factor of 10 (2 x 5), the product will have 5 zeros at the end.

Answer

The product of all natural numbers from 9 to 29 has 5 zeros at the end.