Question

Васе купили аквариум в форме куба вмещающий в себя 64 литра воды (1 литр = 1 дм3 ) вася наполнил аквариум водой не долив 5 см до верхнего края сколько литров воды он налил в аквариум? Очень срочно!

Answer 1

V=64дм³=4*4*4 дм³
значит высота аквариума=4 дм =40 см 
40-5=35 cм
вода налитая в аквариум имеет форму прямоугольного параллелепипеда у которого измерения равны 40, 40, 35 см
Vводы=40*40*35=56000 см³ или 4*4*3,5=56 дм³

Answer 2

Calculation of Water Volume in the Aquarium

To calculate the volume of water that Vasya poured into the aquarium, we need to subtract the empty space at the top of the aquarium from the total volume of the aquarium.

Given: - The aquarium is in the shape of a cube. - The aquarium can hold 64 liters of water. - 1 liter is equal to 1 cubic decimeter (dm^3). - Vasya did not fill the aquarium to the top, leaving a 5 cm gap.

To calculate the volume of water Vasya poured into the aquarium, we need to subtract the empty space from the total volume of the aquarium.

Calculation Steps:

1. Convert the volume of the aquarium from liters to cubic decimeters (dm^3): - 1 liter = 1 dm^3. - Therefore, the volume of the aquarium is 64 dm^3.

2. Calculate the volume of the empty space at the top of the aquarium: - The aquarium is in the shape of a cube, so each side has the same length. - Let's assume the side length of the cube is 'x' dm. - The volume of the empty space is equal to the volume of the cube with side length 'x' minus the volume of the water poured into the aquarium. - The volume of the empty space is equal to the height of the empty space multiplied by the area of the base of the cube. - The height of the empty space is 5 cm, which is equal to 0.05 dm. - The area of the base of the cube is equal to the side length squared. - Therefore, the volume of the empty space is (x^2) * 0.05 dm^3.

3. Subtract the volume of the empty space from the total volume of the aquarium to find the volume of water poured into the aquarium: - The volume of water poured into the aquarium is equal to the total volume of the aquarium minus the volume of the empty space. - The volume of water poured into the aquarium is 64 dm^3 minus (x^2) * 0