Question

EF перпендикулярно KO угол AOB равен 70 градусов и угол AOK равен 30 градусом Найдите углы AOE BOF

Answer 1

80 и 90 градусов. Ща решение кину

Answer 2

Given Information:

We are given the following information: - EF is perpendicular to KO. - The angle AOB is 70 degrees. - The angle AOK is 30 degrees.

Solution:

To find the angles AOE and BOF, we need to analyze the given information and use some geometric principles.

First, let's consider the triangle AOB. We know that the sum of the angles in a triangle is 180 degrees. So, we can find the third angle, ABO, by subtracting the given angles AOB and ABO from 180 degrees:

ABO = 180 - AOB - AOK

Substituting the given values, we have:

ABO = 180 - 70 - 30 = 80 degrees

Now, let's consider the triangle AOE. We know that the sum of the angles in a triangle is 180 degrees. So, we can find the third angle, EOA, by subtracting the given angles AOE and AEO from 180 degrees:

EOA = 180 - AOE - AEO

Since EF is perpendicular to KO, angle AEO is a right angle (90 degrees). Therefore, we have:

EOA = 180 - AOE - 90 = 90 - AOE

Now, let's consider the triangle BOF. We can use the same reasoning as above to find the third angle, FOB:

FOB = 180 - BOF - BFO

Since EF is perpendicular to KO, angle BFO is a right angle (90 degrees). Therefore, we have:

FOB = 180 - BOF - 90 = 90 - BOF

To find the values of AOE and BOF, we need to find the values of EOA and FOB. We can do this by substituting the values we found earlier:

EOA = 90 - AOE FOB = 90 - BOF

Since we know that the sum of the angles in a triangle is 180 degrees, we can write the following equation:

ABO + AOE + BOF = 180

Substituting