
У коробці лежать 42 олівці з них 14 олівців червоні 16 олівців сині а решта зелені Яка ймовірність
того щ навмання взятий олівець не буде ні червоним ні синім СРОЧНО ТРЕБА

Ответы на вопрос




I can answer your question in detail. You have a box with 42 pencils, of which 14 are red, 16 are blue, and the rest are green. You want to know the probability that a randomly chosen pencil will not be either red or blue. Here is how you can solve this problem:
- First, you need to find out how many green pencils are in the box. You can do this by subtracting the number of red and blue pencils from the total number of pencils. That is, 42 - 14 - 16 = 12. So there are 12 green pencils in the box. - Next, you need to find out the fraction of green pencils out of all the pencils in the box. You can do this by dividing the number of green pencils by the total number of pencils. That is, 12 / 42 = 0.2857. This fraction is also called the relative frequency of green pencils in the box. - Finally, you need to convert the fraction into a percentage, which is the probability that you are looking for. You can do this by multiplying the fraction by 100. That is, 0.2857 x 100 = 28.57%. This means that there is a 28.57% chance that a randomly chosen pencil will not be either red or blue.
I hope this helps you understand the solution. You can also check out some web search results that explain the same problem in different ways . Have a nice day!


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