
Запиши каждое предложиние уровнением и реши его Неизвестное число уменьшели на 708 и получили 1200
Число 834 уменьшили на несколько единиц и получили 829 Неизвестное число уменьшили в 19 раз и получили 607 К неизвестному числу добавили 175 и получили 207

Ответы на вопрос

834—Х=829
Х:19=607 или Х—19=607
(1 уравнение для 4—5 классов)
Х+175=207



Equations and Solutions:
Let's solve each equation step by step:
1. Unknown number decreased by 708 and resulted in 1200: Let the unknown number be represented by x. The equation can be written as: x - 708 = 1200. To solve for x, we can add 708 to both sides of the equation: x - 708 + 708 = 1200 + 708. Simplifying the equation gives us: x = 1908.
2. Number 834 decreased by several units and resulted in 829: Let the number of units by which 834 is decreased be represented by y. The equation can be written as: 834 - y = 829. To solve for y, we can subtract 829 from both sides of the equation: 834 - y - 829 = 829 - 829. Simplifying the equation gives us: y = 5.
3. Unknown number decreased by 19 times and resulted in 607: Let the unknown number be represented by z. The equation can be written as: z / 19 = 607. To solve for z, we can multiply both sides of the equation by 19: (z / 19) * 19 = 607 * 19. Simplifying the equation gives us: z = 11533.
4. Unknown number increased by 175 and resulted in 207: Let the unknown number be represented by w. The equation can be written as: w + 175 = 207. To solve for w, we can subtract 175 from both sides of the equation: w + 175 - 175 = 207 - 175. Simplifying the equation gives us: w = 32.
Solutions:
- The unknown number in the first equation is 1908. - The number of units by which 834 is decreased in the second equation is 5. - The unknown number in the third equation is 11533. - The unknown number in the fourth equation is 32.Please let me know if there's anything else I can help you with!


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