Question

Дорога между пунктами А и Б состоит из подъёма и спуска , а её длина равна 19 км. Турист прошёл путь из А в Б за 13 ч. Время его движения на спуске составило 6ч. С какой скоростью турист шёл на спуске, если скорость его движения на подъёме меньше скорости движения на спуске на 1 км.ч

Answer 1

Х-скорость на подъеме
х+1-скорость на спуске

4(х+1)+(5-4)х=19
4х+4+х=19
5х=15
х=15/5=3 км/ч-скорость на подъеме
3+1=4 км/ч-скорость на спуске

Answer 2

Calculation of Speed on Descent

To calculate the speed at which the tourist walked on the descent, we can use the formula:

Speed = Distance / Time

Given that the length of the road between points A and B is 19 km, and the tourist completed the journey in 13 hours, we can calculate the speed on the descent.

Let's denote the speed on the ascent as V_a and the speed on the descent as V_d.

We are also given that the time spent on the descent was 6 hours.

Using the information that the speed on the ascent is 1 km/h less than the speed on the descent, we can set up the following equations:

V_a = V_d - 1

Distance = 19 km

Time = 13 hours

Time on descent = 6 hours

Substituting the values into the formula, we get:

V_d = Distance / Time on descent

V_d = 19 km / 6 hours

Calculating the value, we find:

V_d = 3.17 km/h Therefore, the speed at which the tourist walked on the descent was approximately 3.17 km/h.