Question

за день рабочие трех бригад должны изготовить вместе 2516 деталей. смогут ли они это сделать, если первая бригада изготавливает в день 715 деталей, втлрая бригада изготавливает на 108 деталей меньше, чем первая, а третья в 2 раза больше, чем первая?

Answer 1

715+(715-108)+(715•2)= 2752 

Answer 2

Да, смогут т.к. первая делает 715, вторая 715-108= 607, третья 715*2= 1430
1430+607+715=2752

Answer 3

Problem Analysis

We are given three brigades tasked with manufacturing a total of 2516 parts in a day. The first brigade produces 715 parts, the second brigade produces 108 parts fewer than the first brigade, and the third brigade produces twice as many parts as the first brigade. We need to determine if the three brigades can meet the target of 2516 parts in a day.

Solution

To determine if the three brigades can meet the target of 2516 parts in a day, we need to calculate the total number of parts produced by all three brigades.

Let's calculate the number of parts produced by each brigade:

- The first brigade produces 715 parts. - The second brigade produces 108 parts fewer than the first brigade, so it produces 715 - 108 = 607 parts. - The third brigade produces twice as many parts as the first brigade, so it produces 2 * 715 = 1430 parts.

Now, let's calculate the total number of parts produced by all three brigades:

Total = 715 + 607 + 1430 = 2752 parts.

Answer

The three brigades will be able to produce a total of 2752 parts, which is more than the required 2516 parts. Therefore, they will be able to meet the target of 2516 parts in a day.

Please let me know if you need any further assistance.