Question

Автомобилист за 3 дня проехал 980км. за первые два дня он проехал 725км, а во второй день на 123 км больше чем в третий. какое расcтояние проехал автомобилист за каждый из этих дней.

Answer 1

980-725=255(км)- третий день
255+123=378(км)-второй день
980-(255+378)=347(км)-первый день

Answer 2

Problem Analysis

We are given that a motorist traveled a total distance of 980 km in 3 days. On the first two days, the motorist traveled a total of 725 km, and on the second day, they traveled 123 km more than on the third day. We need to determine the distance traveled by the motorist on each of these three days.

Solution

Let's denote the distance traveled on the first day as x km, the distance traveled on the second day as y km, and the distance traveled on the third day as z km.

From the given information, we have the following equations: 1. The total distance traveled in 3 days is 980 km: x + y + z = 980. 2. The total distance traveled on the first two days is 725 km: x + y = 725. 3. The distance traveled on the second day is 123 km more than on the third day: y = z + 123.

We can solve this system of equations to find the values of x, y, and z.

Substituting equation 3 into equation 2, we get: x + (z + 123) = 725.

Simplifying, we have: x + z = 602.

Substituting this value into equation 1, we get: (602) + y = 980.

Simplifying, we have: y = 378.

Substituting this value of y into equation 2, we get: x + 378 = 725.

Simplifying, we have: x = 347.

Finally, substituting the values of x and y into equation 1, we get: 347 + 378 + z = 980.

Simplifying, we have: z = 255.

Therefore, the motorist traveled: - 347 km on the first day, - 378 km on the second day, and - 255 km on the third day.

Answer

The motorist traveled 347 km on the first day, 378 km on the second day, and 255 km on the third day.