Question

На одному дитячому майданчику гралося 32 дитини,на другому _ у 2 рази менше , ніж на першому , а на третьому_ на 19менше , ніж на першому ш другому разом .Скільки дітей гралось на третьому майданчику?

Answer 1

1) 32:2=16 (д) игралось на второй площадке
2) 32+16=48 (д) на первой и второй площ. вместе
3)48-19=29 (д) играли на 3 площ.

Answer 2

32·2=64на 2 майданчыку 
32+64=98на 2 майданчыках разом 
98 - 19=79 дитей гралося на 3 майданчыку

Answer 3

According to Google Translate, the text you entered is in Ukrainian and it means:

Answer in detail. On one playground, 32 children played, on the second _ 2 times less than on the first, and on the third _ 19 less than on the first and second together. How many children played on the third playground?

To solve this problem, we can use the following steps:

- Let x be the number of children who played on the second playground. Then, we have x = 32 / 2 = 16, since the second playground had 2 times less children than the first one. - Let y be the number of children who played on the third playground. Then, we have y = 32 + 16 - 19 = 29, since the third playground had 19 less children than the first and second together. - Therefore, the answer is 29 children played on the third playground.