Question

Помогите решить -2а-(7-2а)= -2а-2(-а+7)+14= 3(-2х-4)+2(3х+8)+2х=

Answer 1

-2а-(7-2а)=-2а-7+2а=7
-2а-2(-а+7)+14=-2а-((-2а)+14)+14=-2а-(-2а)-14+14=0
3(-2х-4)+2(3х+8)+2х=-6х-12+6х+16+2х=-12+16+2х=4+2х

Answer 2

-2a - (7 - 2a) = -2a - 2(-a + 7) + 14 First, let's simplify the equation step by step.

-2a - (7 - 2a) = -2a - 2(-a + 7) + 14 -2a - 7 + 2a = -2a + 2a - 14 + 14 -7 = 0

Now, let's solve the second equation:

3(-2x - 4) + 2(3x + 8) + 2x -6x - 12 + 6x + 16 + 2x 2x + 4

So, the final equation is: -7 = 0 2x + 4

Since the equation -7 = 0 is not true, there is no solution for this system of equations.