
А)(6-2 1/10•2 1/7)•4/15 б)(2 2/3 -2 2/9)•(2-1 1/2) подробно решите пж


Ответы на вопрос




Solution:
Let's solve the given expressions step by step:
a) (6-2+1/10•2+1/7)•4/15
First, let's simplify the expression inside the parentheses:
6 - 2 + 1/10 • 2 + 1/7
= 4 + 1/10 • 2 + 1/7
= 4 + 1/5 + 1/7
Next, let's simplify the expression inside the parentheses further:
4 + 1/5 + 1/7
To add fractions, we need a common denominator. The least common multiple of 5 and 7 is 35. So, let's convert the fractions to have a denominator of 35:
= 4/1 • 7/7 + 1/5 • 7/7 + 1/7 • 5/5
= 28/35 + 7/35 + 5/35
Now, we can add the fractions:
= (28 + 7 + 5)/35
= 40/35
= 8/7
Finally, let's multiply the result by 4/15:
(8/7) • (4/15)
To multiply fractions, we simply multiply the numerators and denominators:
= (8 • 4)/(7 • 15)
= 32/105
Therefore, the value of a) (6-2+1/10•2+1/7)•4/15 is 32/105.
b) (2+2/3+-2+2/9)•(2-1+1/2)
First, let's simplify the expression inside the parentheses:
2 + 2/3 + (-2) + 2/9
= 2 + 2/3 - 2 + 2/9
Next, let's simplify the expression inside the parentheses further:
2 + 2/3 - 2 + 2/9
To add and subtract fractions, we need a common denominator. The least common multiple of 3 and 9 is 9. So, let's convert the fractions to have a denominator of 9:
= 2/1 • 3/3 + 2/3 • 3/3 - 2/1 • 9/9 + 2/9 • 1/1
= 6/9 + 6/9 - 18/9 + 2/9
Now, we can add and subtract the fractions:
= (6 + 6 - 18 + 2)/9
= -4/9
Finally, let's multiply the result by the expression outside the parentheses:
(-4/9) • (2 - 1 + 1/2)
= (-4/9) • (2/1 - 1/1 + 1/2)
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