Question

Один бак містить 99л бензину, а другий бак містить 57л. Із першого баку щодня виливали по 12 л. а з другого - по 10 л. Через скільки днів у першому баці буде в 3 рази більше бензину, ніж у другому

Answer 1

Х количество дней
12х выльют из первого бака
10х из второго
99-12х=3(57-10х)
99-12х=171-30х
18х=72
х=4 дня
Ответ: через 4 дня

Answer 2

Problem Analysis

To solve this problem, we need to determine the number of days it will take for the first tank to have three times as much gasoline as the second tank. We are given that the first tank initially contains 99 liters of gasoline, and 12 liters are poured out each day. The second tank initially contains 57 liters of gasoline, and 10 liters are poured out each day.

Solution

Let's calculate the number of days it will take for the first tank to have three times as much gasoline as the second tank.

1. Calculate the number of liters poured out from the first tank each day: - 12 liters are poured out each day from the first tank.

2. Calculate the number of liters poured out from the second tank each day: - 10 liters are poured out each day from the second tank.

3. Calculate the difference in liters between the two tanks each day: - The difference is 12 - 10 = 2 liters.

4. Calculate the number of days it will take for the first tank to have three times as much gasoline as the second tank: - The first tank needs to have three times as much gasoline as the second tank, which means the difference between the two tanks needs to be 3 times the amount poured out each day. - Let's denote the number of days as "x". - The equation to solve is: 2x = 3 * (99 - x * 12). - Simplifying the equation: 2x = 297 - 36x. - Combining like terms: 38x = 297. - Solving for x: x = 297 / 38 ≈ 7.82.

Answer

It will take approximately 7.82 days for the first tank to have three times as much gasoline as the second tank.