Question

Реши задачу с помощью уравнения. Ящерица агама в течении суток съедает 180 г. насекомых , а пауков в 4 раза большеи. Сколько всего граммов насекомых и пауков съедает ящерица агама в сутки?

Answer 1

180+(180×4)=180×5=900

Answer 2

180*4=720
720+180=900

Answer 3

Problem Analysis

To solve this problem, we need to determine the total weight of insects and spiders that the agama lizard consumes in a day. We are given that the agama lizard eats 180 grams of insects, and the number of spiders it eats is four times the number of insects.

Solution

Let's assume the weight of each insect is x grams. Since the agama lizard eats 180 grams of insects, we can set up the following equation:

180 = x * number of insects We are also given that the number of spiders is four times the number of insects. Let's represent the number of insects as n. Therefore, the number of spiders is 4n. Since the weight of each spider is four times the weight of each insect, we can set up the following equation:

4n * 4x = 4 * 4 * x * n = 16nx To find the total weight of insects and spiders, we need to add the weight of insects and the weight of spiders. The weight of insects is given as 180 grams, and the weight of spiders can be calculated by multiplying the number of spiders by the weight of each spider, which is 4 times the weight of each insect.

Let's substitute the value of n from equation into equation to find the weight of spiders:

16nx = 16 * 180 = 2880 grams Now, we can calculate the total weight of insects and spiders by adding the weight of insects (180 grams) and the weight of spiders (2880 grams):

Total weight = 180 + 2880 = 3060 grams

Therefore, the agama lizard consumes a total of 3060 grams of insects and spiders in a day.

Answer

The agama lizard consumes a total of 3060 grams of insects and spiders in a day.