Question

Велосипедист и мотоциклист выехали одновременно на встречу друг к другу из двух поселков. Велосипедист ехал со средней скоростью 12км/ч, а мотоциклист 40км/ч. 1) Найди среднюю скорость их сближения? 2) На сколько километров велосипедист и мотоциклист приблизятся друг к другу за 2 часа?

Answer 1

12+40=52(скор) скорость сближения .52*2=104(км) сблизятся за 2 ч

Answer 2

1) 12+40 = 52 км/ч средняя скорость сближения
2) 52*2 = 104 км проедут за 2 часа

Answer 3

Calculating the Average Speed of Approach

To find the average speed of their approach, we can use the formula: Average speed = Total distance / Total time

The total distance covered by both the cyclist and the motorcyclist is the sum of the distances each has traveled. The total time is the same for both.

The cyclist's speed is 12 km/h, and the motorcyclist's speed is 40 km/h.

Using the formula: Average speed = (Speed of cyclist + Speed of motorcyclist) / 2

Average speed = (12 + 40) / 2 Average speed = 26 km/h.

Calculating the Distance Covered in 2 Hours

To find the distance covered in 2 hours, we can use the formula: Distance = Speed × Time

For the cyclist: Distance = 12 km/h × 2 h Distance = 24 km

For the motorcyclist: Distance = 40 km/h × 2 h Distance = 80 km

The total distance covered by both in 2 hours is: Total distance = Distance covered by cyclist + Distance covered by motorcyclist Total distance = 24 km + 80 km Total distance = 104 km.

Therefore, the cyclist and the motorcyclist will be approximately 104 kilometers closer to each other after 2 hours.

I hope this helps! If you have further questions, feel free to ask.