Question

97 1/6 + 11/39 - 6 8/13 -10/21 × (9/16 +3,075 × 0,5) : 1/83=

Answer 1

97 1/6 + 11/39 - 6 8/13 -10/21 × (9/16 +3,075 × 0,5) ÷ 1/83= 7 5/6
4)1÷1/83=1×83=83
5)97 1/6  +  11/39 = 583/6  +  11/39 =(583 × 13  +  11 × 2)/78 = 7579/78 +  22/78 =  7601/78 = 97 35/78
6)97 35/78  -  6 8/13 = 7601/78  -  86/13 =(7601 × 1  -  86 × 6)/78 = 7601/78  -  516/78 =  7085/78 = 545/6 = 90 5/6
7)90 5/6  -  83 = 545/6  -  83 =(545 × 1  -  83 × 6)/6 = 545/6  -  498/6 =  47/6 = 7 5/6

Answer 2

1)3,075*0,5=1,5375
2)9/16+1,5375=0,5625+1,5375=2,1
3)10/21*2,1=10/21*21/10=1
4)1:1/83=83
5)97 1/6+11/39-6 8/13=97 13/78+22/78-6 48/78=97 35/78-6 48/78=
=96 113/78-6 48/76=90 65/78=90 5/6
6)90 5/6-83=7 5/6

Answer 3

I can help you with math problems. Here is the detailed solution for your question:

$$97\frac{1}{6}+\frac{11}{39}-6\frac{8}{13}-\frac{10}{21}\times\left(\frac{9}{16}+3.075\times 0.5\right)+\frac{1}{83}=$$

First, we simplify the fractions by finding the lowest common denominator (LCD) for each group of fractions.

$$\frac{1}{6}+\frac{11}{39}=\frac{13}{78}$$

$$\frac{8}{13}-\frac{10}{21}=\frac{14}{273}$$

$$\frac{9}{16}+3.075\times 0.5=\frac{123}{80}$$

$$\frac{1}{83}=\frac{1}{83}$$

Next, we perform the multiplication and division operations from left to right.

$$-\frac{10}{21}\times\frac{123}{80}=-\frac{41}{56}$$

Then, we add and subtract the fractions and the whole numbers from left to right.

$$97+\frac{13}{78}-6-\frac{14}{273}+\frac{1}{83}=91\frac{169}{18252}$$

$$-\frac{41}{56}=-\frac{41}{56}$$

Finally, we add the two remaining terms.

$$91\frac{169}{18252}-\frac{41}{56}=90\frac{10001}{18252}$$

Therefore, the final answer is:

$$97\frac{1}{6}+\frac{11}{39}-6\frac{8}{13}-\frac{10}{21}\times\left(\frac{9}{16}+3.075\times 0.5\right)+\frac{1}{83}=90\frac{10001}{18252}$$

I hope this helps you understand the problem better. If you have any other questions, feel free to ask me.Ответь+подробно.+97+1/6+++11/39+-+6+8/13+-10/21+×+(9/16++3,075+×+0,5)+:+1/83=