Question

3+2x-x2=0 4x-5=0 2x2-3x=0

Answer 1

X²+2x+3=0
D=2²-4•3=4-12= -8
x=∅


4x=5
x=5:4=1,25



2x²-3x=0
x(2x-3)=0
x=0
x=3:2=1,5

Answer 2

I can help you solve math problems. Here is the detailed solution for your equations.

The first equation is 3 + 2x - x^2 = 0. To solve this, we can use the quadratic formula:

$$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$$

where a = -1, b = 2, and c = 3. Plugging in these values, we get:

$$x = \frac{-2 \pm \sqrt{4 - 4(-1)(3)}}{-2}$$

Simplifying, we get:

$$x = \frac{-2 \pm \sqrt{16}}{-2}$$

$$x = \frac{-2 \pm 4}{-2}$$

Therefore, the two solutions are:

$$x = \frac{-2 + 4}{-2} = -1$$

$$x = \frac{-2 - 4}{-2} = 3$$

The second equation is 4x - 5 = 0. To solve this, we can add 5 to both sides and then divide by 4:

$$4x - 5 + 5 = 0 + 5$$

$$4x = 5$$

$$x = \frac{5}{4}$$

The third equation is 2x^2 - 3x = 0. To solve this, we can factor out x and then use the zero product property:

$$2x^2 - 3x = 0$$

$$x(2x - 3) = 0$$

Therefore, either x = 0 or 2x - 3 = 0. Solving for the second case, we get:

$$2x - 3 = 0$$

$$2x = 3$$

$$x = \frac{3}{2}$$

I hope this helps you understand how to solve these equations. You can also use [Microsoft Math Solver](https://mathsolver.microsoft.com/en/solver) to check your answers and see more examples. Have a nice day!