Question

Из улья вылетела пчела со скоростью 8 м/с.Через 30 секунд вылетела вторая пчела полетев со скорость 9 м/с.Через какое время вторая пчела догонит первую

Answer 1

8*(30+х)=9Х
Х=240
ответ: 240 секунд

Answer 2

Problem Analysis

We are given that a bee flies out of the hive with a speed of 8 m/s, and after 30 seconds, another bee flies out with a speed of 9 m/s. We need to determine how long it will take for the second bee to catch up to the first bee.

Solution

To solve this problem, we can set up an equation based on the distance traveled by each bee. Let's assume that the time it takes for the second bee to catch up to the first bee is t seconds.

The distance traveled by the first bee in t seconds can be calculated using the formula: distance = speed × time. Therefore, the distance traveled by the first bee is 8t meters.

Similarly, the distance traveled by the second bee in t seconds is 9t meters.

Since the second bee catches up to the first bee, the distances traveled by both bees must be equal. Therefore, we can set up the equation:

8t = 9t

Simplifying the equation, we get:

9t - 8t = 0

t = 0

The equation simplifies to t = 0, which means that the second bee catches up to the first bee instantly. This implies that the second bee starts ahead of the first bee.

Therefore, the second bee catches up to the first bee immediately after it starts flying.

Answer

The second bee catches up to the first bee immediately after it starts flying.