Question

БЕЛОЧКА ЗАЯЦ И ОЛЕНЁНОК СДЕЛАЛИ ЛОДКУ ГРУЗОПОДЪЁМНОСТЬЮ 30 КГ ... МАССА БЕЛОЧКИ СОСТАВЛЯЕТ 6 % ОТ МАССЫ ЗАЙЦА ,,, А МАССА ЗАЙЦА РАВНА 3 / 25 МАССЫ ОЛЕНЁНКА ...... МОГУТ ЛИ ОНИ ОТПРАВИТЬСЯ В ПУТЕШЕСТВИЕ ПО РЕКЕ НА НА СВОЕЙ ЛОДКЕ , ЕСЛИ МАССА БЕЛОЧКИ РАВНА 180 ГРАММ

Answer 1

1) 180:6*100=3000 (г) - масса зайца

2) 3000:3*25=25000 (г) - масса оленёнка

3) 180+3000+25000=28180 (г) - масса всех троих

28180 г=28 кг 180 г

28 кг 180 г < 30 кг

Ответ: да, могут.

Answer 2

1) 180 : 6 * 100 = 3000 ( г ) - масса зайца  2) 3000 : 3 * 25 = 25000 ( г ) - масса олененка  3) 180 + 3000 + 25000 = 28180 ( г ) - масса всех троих   Ответ : да , можно

Answer 3

Analysis and Solution

To determine if the squirrel, hare, and fawn can embark on a river journey in their boat, we need to compare the total weight of the three animals to the carrying capacity of the boat.

Given the following information: - The boat has a carrying capacity of 30 kg. - The squirrel's weight is 6% of the hare's weight. - The hare's weight is 3/25 of the fawn's weight. - The squirrel's weight is 180 grams.

Let's calculate the weights of the hare and fawn and then determine if the total weight of the three animals exceeds the carrying capacity of the boat.

Calculation

Let's assign variables to the weights of the hare (H) and the fawn (F).

We know that the squirrel's weight (S) is 6% of the hare's weight, so we can write the equation:

S = 0.06 * H

We also know that the hare's weight is 3/25 of the fawn's weight, so we can write the equation:

H = (3/25) * F

Given that the squirrel's weight is 180 grams, we can substitute this value into the equation for S:

180 = 0.06 * H

Solving this equation, we find:

H = 180 / 0.06 = 3000 grams

Now, substituting the value of H into the equation for H:

3000 = (3/25) * F

Solving this equation, we find:

F = (3000 * 25) / 3 = 25000 grams

Converting the weights to kilograms:

Squirrel's weight = 180 grams = 0.18 kg Hare's weight = 3000 grams = 3 kg Fawn's weight = 25000 grams = 25 kg

Conclusion

The total weight of the squirrel, hare, and fawn is 0.18 kg + 3 kg + 25 kg = 28.18 kg.

Since the total weight of the three animals is less than the carrying capacity of the boat (30 kg), they can embark on a river journey in their boat.