Question

-xкв-12x=0 help me plees

Answer 1

-x^2-12x=0, -x(x+12)=0, -x=0 или (x+12)=0, x1=0/-1=0. x+12=0, x2= -12. Ответ: x1=0, x2= -12.

Answer 2

I can help you solve the equation -x^2-12x=0. Here are the steps:

1. First, we need to find the discriminant of the equation, which is the part under the square root in the quadratic formula. The discriminant is b^2-4ac, where a, b, and c are the coefficients of the equation. In this case, a=-1, b=-12, and c=0. So, the discriminant is (-12)^2-4(-1)(0) = 144. 2. Next, we need to apply the quadratic formula, which is x = (-b ± √d) / 2a, where d is the discriminant. In this case, x = (-(-12) ± √144) / 2(-1) = (12 ± 12) / -2. 3. Then, we need to simplify the expression and find the two possible values of x. We have x = (12 + 12) / -2 or x = (12 - 12) / -2. Simplifying, we get x = -12 or x = 0. 4. Finally, we need to check if the solutions are valid by plugging them back into the original equation. If we plug in x = -12, we get -(-12)^2-12(-12) = 0, which is true. If we plug in x = 0, we get -(0)^2-12(0) = 0, which is also true. Therefore, both solutions are valid and the equation has two real roots: x = -12 or x = 0.

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