Question

А^2-9 в^2+18 вс-9 с^2 помогите решить

Answer 1

а^2-9 в^2+18 вс-9 с^2

а^2+(-9 в^2+18 вс-9 с^2)

У слагаемых, заключённых в скобки, вынесем за скобки (-9)

а^2-9(в^2-2вс+с^2)

То,что в скобках, раскладываем по формуле х^2+2ху+у^2=(х+у)^2 :

а^2-9 [(в-с)^2]

Известно, что 9=3^2, значит:

а^2-9 [(в-с)^2] = а^2-[(3*(в-с)]^2

Разность квадратов раскладываем по формуле х^2 - у^2=(х-у)(х+у) :

[а-3*(в-с)]*[а+3*(в-с)]

Больше не раскладывается

Answer 2

Solving the Equation

To solve the equation A^2 - 9 + B^2 + 18 + C^2 - 9 = 0, we can start by simplifying it step by step.

First, let's rewrite the equation in a more organized form: A^2 + B^2 + C^2 - 9 + 18 - 9 = 0

Now, let's simplify the equation: A^2 + B^2 + C^2 = 0

This equation suggests that the sum of the squares of A, B, and C is equal to zero. In the real number system, the square of any real number is non-negative, and the only way for the sum of squares to be zero is if each individual square is also zero.

Therefore, the solution to the equation is: A = 0, B = 0, C = 0

This means that for the given equation to hold true, A, B, and C must all be equal to zero.

Conclusion

The solution to the equation A^2 - 9 + B^2 + 18 + C^2 - 9 = 0 is A = 0, B = 0, C = 0.