Question

1) |х+1|<0,3 2)|зх+7|>7 3)|4х-2|=6 4)||2х+3|-5|=3 Решите пожалуйста

Answer 1

1) |0,3>(x+1)|

2) x ∈ (-∞, - 14/3)∪(0,∞)

3) х ∈ {-1.2}

4) х ∈ {-11/2, -5/2, -1/2,5/2}
Вот это ответы а решение не знаю

Answer 2

Solving the Equations

To solve the given equations, let's address each one separately.

1) |x + 1| < 0.3 2) |2x + 7| > 7 3) |4x - 2| = 6 4) |2x + 3| - 5 = 3

Solution

1) |x + 1| < 0.3 - The solution to this inequality is an empty set because the absolute value of any real number cannot be less than a positive number. - Therefore, there are no solutions for this inequality.

2) |2x + 7| > 7 - To solve this inequality