Question

В двух вазах 70 слив. Когда из одной вазы взяли 20 слив.то в вазаъ слив осталось поровну. Сколько слив было в КАЖДОЙ вазе сначала?

Answer 1

70-20=50 слив

50/2=25 слив в одной вазе

25+20=45 слив во второй вазе

Ответ 25 и 45 слив было сначала

Answer 2

Problem Analysis

We are given two vases, each containing 70 sliw. When 20 sliw are taken from one vase, the remaining sliw in both vases are equal. We need to determine the initial number of sliw in each vase.

Solution

Let's assume that the initial number of sliw in the first vase is x and the initial number of sliw in the second vase is y.

According to the given information, when 20 sliw are taken from one vase, the remaining sliw in both vases are equal. This can be expressed as:

x - 20 = y + 20 Simplifying the equation, we get:

x - y = 40 We also know that the total number of sliw in both vases is 70. This can be expressed as:

x + y = 70 Now we have a system of two equations with two variables. We can solve this system of equations to find the values of x and y.

Solving the System of Equations

To solve the system of equations, we can use the method of substitution or elimination. Let's use the method of elimination.

Adding the two equations together, we get:

(x - y) + (x + y) = 40 + 70

Simplifying, we get:

2x = 110

Dividing both sides by 2, we get:

x = 55

Substituting the value of x back into one of the original equations, we can solve for y:

55 + y = 70

Subtracting 55 from both sides, we get:

y = 15

Therefore, the initial number of sliw in the first vase was 55 and the initial number of sliw in the second vase was 15.

Answer

The initial number of sliw in each vase was 55 and 15 respectively.