Question

Дано равенство: 24/7=3(остаток 2)-деление выполнено неправильно. Вопрос: выполни деление правильно и укажи в скобках, сколько раз делитель укладывается в "неправильном" остатке. Те в данном примере, сколько раз цифра 7 (делитель) укладывается в цифре 2( неправильный остаток)?!!??? Непонятен вопрос.... Как 7 может уложится в 2, а не наоборот? Или надо по-другому решать? Подскажите!

Answer 1

Вообще ответ тут простой

24/7 целиком не делиться, 21 ближайшее, остаток у нас 3, вообщем так,

24/7=33(ост. 3) в этом ошибка.

Answer 2

Division Problem with Remainder

It seems like there's a misunderstanding in the given division problem. Let's clarify and solve the problem step by step.

Given Equation: 24/7 = 3 (remainder 2)

Correcting the Division

To solve the division problem correctly, we need to divide 24 by 7 and find the remainder. Let's perform the division:

24 ÷ 7 = 3 with a remainder of 3

So, the correct division result is 3 with a remainder of 3, not 2 as initially stated.

Understanding the Question

Now, let's address the question about how many times the divisor (7) fits into the "incorrect" remainder of 2. It's important to note that the remainder cannot be larger than the divisor in a correct division.

Clarifying the Misunderstanding

It seems there might be a misunderstanding in the original question. The remainder cannot be larger than the divisor in a correct division. Therefore, the question about how many times the digit 7 (the divisor) fits into the digit 2 (the "incorrect" remainder) doesn't align with the principles of division.

Proposed Resolution

To resolve this, we can correct the division and then discuss any related concepts or alternative approaches to the problem. If there's a specific method or concept you'd like to explore further, feel free to let me know!

Let's proceed with the corrected division and any additional explanations or discussions you may need.