Question

В двух сосудах 35 литров воды во втором в 1 ,1/3 меньше чем в первом. сколько воды в каждом сосуде?

Answer 1

Х - первый сосуд
х÷1 1/3 - второй сосуд

х+(х÷1 1/3)=35
х+х×3/4=35
(4х+3х)/4=35
7х=140
х=140÷7=20 л в первом сосуде

35-20=15 л во втором сосуде

Answer 2

Что значит "во втором в 1" ?

Answer 3

Problem Analysis

We have two vessels, with the second vessel containing 1/3 less water than the first, and the total amount of water in both vessels is 35 liters. We need to find out how much water is in each vessel.

Solution

Let's denote the amount of water in the first vessel as x liters. Then, the amount of water in the second vessel would be (x - 1/3x), which simplifies to (2/3x) liters. We know that the total amount of water in both vessels is 35 liters, so we can set up the equation:

x + 2/3x = 35

Solving this equation will give us the amount of water in each vessel.

Calculation

Let's solve the equation: x + 2/3x = 35

Combining like terms: 5/3x = 35

Multiplying both sides by 3/5 to isolate x: x = 35 * 3/5

Solving for x: x = 21

Now, we can find the amount of water in the second vessel: (2/3) * 21 = 14

Answer

So, the amount of water in the first vessel is 21 liters, and the amount of water in the second vessel is 14 liters.