
Помогите решить пример: 1)2x-15=13 2)7y-25=45 3)130-4x=70 За ранее спасибо


Ответы на вопрос

х=28÷2
х=14
2×14-15=13
13=13
2)7у=45+25
у=70÷7
у=10
3)4х=130-70
х=60÷4
х=15






Solution to the Equations:
Let's solve the given equations step by step:
1) 2x - 15 = 13
To solve for x, we need to isolate the variable on one side of the equation.
Adding 15 to both sides of the equation:
2x - 15 + 15 = 13 + 15
Simplifying:
2x = 28
Dividing both sides of the equation by 2:
2x/2 = 28/2
Simplifying:
x = 14
Therefore, the solution to the equation 2x - 15 = 13 is x = 14.
2) 7y - 25 = 45
To solve for y, we need to isolate the variable on one side of the equation.
Adding 25 to both sides of the equation:
7y - 25 + 25 = 45 + 25
Simplifying:
7y = 70
Dividing both sides of the equation by 7:
7y/7 = 70/7
Simplifying:
y = 10
Therefore, the solution to the equation 7y - 25 = 45 is y = 10.
3) 130 - 4x = 70
To solve for x, we need to isolate the variable on one side of the equation.
Subtracting 130 from both sides of the equation:
130 - 4x - 130 = 70 - 130
Simplifying:
-4x = -60
Dividing both sides of the equation by -4:
-4x/-4 = -60/-4
Simplifying:
x = 15
Therefore, the solution to the equation 130 - 4x = 70 is x = 15.
In summary, the solutions to the given equations are: 1) x = 14 2) y = 10 3) x = 15
I hope this helps! Let me know if you have any further questions.


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